33s^2+96s=0

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Solution for 33s^2+96s=0 equation:



33s^2+96s=0
a = 33; b = 96; c = 0;
Δ = b2-4ac
Δ = 962-4·33·0
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-96}{2*33}=\frac{-192}{66} =-2+10/11 $
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+96}{2*33}=\frac{0}{66} =0 $

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